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Mathematics Problems and Solutions ( U . K . Z . M )

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Two externally tangent circle

Given : M is the midpoint of BC and as shown in figure . Prove: BC = 2 AF Solution Given : M is the midpoint of BC and as shown in fig...
Descartes' Circle Theorem

$\displaystyle \alpha +\beta +\gamma =2\pi$ $\displaystyle \cos 2\alpha +\cos 2\beta +\cos 2\gamma$ $ \displaystyle =2{{\cos }...
Sines Law , Componendo and Dividendo

ABC is a triangle having BC = 2 AB . Bisect BC in D and BD in E . Prove that AD bisects $\displaystyle \angle \ CAE.$ Solution...