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Sunday, February 10, 2019

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at February 10, 2019 No comments:
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  • Descartes' Circle Theorem
    $ \displaystyle \alpha +\beta +\gamma =2\pi $ $ \displaystyle \cos 2\alpha +\cos 2\beta +\cos 2\gamma $ $ \displaystyle =2{{\cos }...
  • Two externally tangent circle
    Given : M is the midpoint of BC and as shown in figure . Prove: BC = 2 AF Solution Given : M is the midpoint of BC and as shown in fig...
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