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Sunday, February 10, 2019

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  • Sines Law , Componendo and Dividendo
    ABC is a triangle having  BC = 2 AB . Bisect  BC  in  D  and  BD  in  E . Prove that  AD  bisects  $\displaystyle \angle \ CAE.$ Solution...
  • Two externally tangent circle
    Given : M is the midpoint of BC and as shown in figure . Prove: BC = 2 AF Solution Given : M is the midpoint of BC and as shown in fig...
  • 45-45 right triangle and Pythagoras theorem
    ABCD is a square and E is the intersection point of the diagonals . If N is any point on AE , show that $\displaystyle A{{B}^{2}}-B{{N}^{2}}...

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