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Tuesday, December 11, 2018

Geometry

Two intersecting circles \displaystyle {{C}_{1}}\ \text{and  }{{C}_{2}} have a common tangent which touches \displaystyle {{C}_{1}}\ \text{at  }P\ \ \text{and  }{{C}_{2}}\ \ \text{at  }Q. The two circles intersect at M and N , where N is nearer to PQ then M . The line PN meets the circle \displaystyle \text{ }{{C}_{2}} again at R . Prove that MQ bisects \displaystyle \angle PMR .



\displaystyle \text{Proof : Join  }MN\text{  and   }QR.

\displaystyle \ \ \ \ \ \ \ \ \ \ \theta =\beta \ \ (\text{angle between tangent and chord = }

\displaystyle \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{angle in the alternate segment )}

\displaystyle \ \ \ \ \ \ \ \ \ \ \phi =\gamma \ \ \ \ \text{( same arc }QN\ )

\displaystyle \ \ \ \ \ \ \ \ \ \ \text{In }\Delta \ PQR,\ \ \ \theta +\phi =\Omega

\displaystyle \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \beta +\gamma =\Omega

\displaystyle \ \ \ \ \ \ \ \ \ \ \Omega =\alpha \text{ }\ (\text{angle between tangent and chord = }

\displaystyle \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{angle in the alternate segment )}

\displaystyle \ \ \ \ \ \ \ \ \ \ \beta +\gamma =\alpha

\displaystyle \ \ \ \ \ \ \ \ \ \therefore \ MQ\ \ \text{bisects   }\angle PMR.


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